JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The resistance \(\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}}\) where \(\mathrm{V}=(200 \pm 5) \mathrm{V}\) and \(I=(20 \pm 0.2) A\), the percentage error in the measurement of \(R\) is _______.
- A \(3.5 \%\)
- B \(7 \%\)
- C \(3 \%\)
- D \(5.5 \%\)
Answer & Solution
Correct Answer
(A) \(3.5 \%\)
Step-by-step Solution
Detailed explanation
\(\mathrm{R}=\frac{\mathrm{V}}{1}\) According to error analysis \( \frac{\mathrm{dR}}{\mathrm{R}}=\frac{\mathrm{dV}}{\mathrm{V}}+\frac{\mathrm{dI}}{\mathrm{I}} \) \( \frac{\mathrm{dR}}{\mathrm{R}}=\frac{5}{200}+\frac{0.2}{20} \) \( \frac{\mathrm{dR}}{\mathrm{R}}=\frac{7}{200} \)…
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