ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2026
  • Easy
  • MCQ

A biconvex lens is formed by using two thin planoconvex lenses, as shown in the figure. The refractive index and radius of curved surfaces are also mentioned in figure. When an object is placed on the left side of lens at a distance of 30 cm from the biconvex lens, the magnification of the image will be :
image

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(-2\)

Step-by-step Solution

Detailed explanation


\(\frac{1}{v}-\frac{1}{u}=\frac{1}{f_{net}}=\frac{1}{f_{1}}+\frac{1}{f_{2}}\)
\(\frac{1}{v}+\frac{1}{30}=(1.5-1)(\frac{1}{15}-\frac{1}{\infty})+(1.2-1)(\frac{1}{\infty}+\frac{1}{12})\)
\(\frac{1}{v}+\frac{1}{30}=\frac{1}{30}+\frac{1}{60}\)
\(v=60\)
\(m=\frac{v}{u}=\frac{60}{-30}=-2\)
Same subject
Explore more questions on app