JEE Mains · Physics · STD 11 - 4.2 friction
A large drum having radius \(R\) is spinning around its axis with angular velocity \(\omega\), as shown in figure. The minimum value of \(\omega\) so that a body of mass M remains stuck to the inner wall of the drum, taking the coefficient of friction between the drum surface and mass M is \(\mu\), is :

- A \( \sqrt{\frac{\mu g}{R}} \)
- B \( \sqrt{\frac{2g}{\mu R}} \)
- C \( \sqrt{\frac{g}{2\mu R}} \)
- D \( \sqrt{\frac{g}{\mu R}} \)
Answer & Solution
Correct Answer
(D) \( \sqrt{\frac{g}{\mu R}} \)
Step-by-step Solution
Detailed explanation
\(N = m \omega^2 r , mg =\mu N\) \(\mu \times m \omega^2 r = mg\) \(\omega=\sqrt{\frac{g}{\mu r}}\)
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