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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A proton of mass \(m\) collides elastically with a particle of unknown mass at rest. After the collision, the proton and the unknown particle are seen moving at an angle of \(90^o\) with respect to each other. The mass of unknown particle is
- A \(\frac{m}{{\sqrt 3 }}\)
- B \(\frac{m}{2}\)
- C \(2m\)
- D \(m\)
Answer & Solution
Correct Answer
(D) \(m\)
Step-by-step Solution
Detailed explanation
Apply principle of conservation of momentum along \(x-direction,\) \(mu=mv_1\) \(\cos {45^ \circ } + M{v_2}\cos {45^ \circ }\) \(mu = \frac{1}{{\sqrt 2 }}\left( {m{v_1} + M{v_2}} \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( i \right)\) Along \(y-direction,\)…
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