JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
In connection with the circuit drawn below, the value of current flowing through \(2\, k \Omega\) resistor is ............. \(\times 10^{-4} A\)
- A \(30\)
- B \(15\)
- C \(25\)
- D \(12\)
Answer & Solution
Correct Answer
(C) \(25\)
Step-by-step Solution
Detailed explanation
Current through \(2 k \Omega\) resistance \(I=\frac{5}{2 \times 10^{3}}=2.5 \times 10^{-3} A\) \(I =25 \times 10^{-4} A\) Ans. \(25\)
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