JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
If \(\mathrm{n}\) is the number density and \(\mathrm{d}\) is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by _______.
- A \(\frac{1}{\sqrt{2 n \pi d^2}}\)
- B \(\sqrt{2} \mathrm{n} \pi \mathrm{d}^2\)
- C \(\frac{1}{\sqrt{2} \mathrm{n} \pi \mathrm{d}^2}\)
- D \(\frac{1}{\sqrt{2} n^2 \pi^2 d^2}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{2} \mathrm{n} \pi \mathrm{d}^2}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n}=\) number of molecule per unit volume \(\mathrm{d}=\) diameter of the molecule \(\lambda=\frac{1}{\sqrt{2} \pi \mathrm{d}^2 \mathrm{n}}\) (By Theory)
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