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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2020
  • Hard
  • Numerical

In a resonance tube experiment when the tube is filled with water up to height of \(17.0\, cm\) from bottom, it resonates with a given tuning fork. When the water level is raised the next resonance with the same tuning fork occurs at a height of \(24.5\, cm\). If the velocity of sound in air is \(330\, m / s ,\) the tuning fork frequency is\(......Hz\)

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Answer & Solution

Correct Answer

(C) \(2200\)

Step-by-step Solution

Detailed explanation

\(\Rightarrow \lambda=2\left(l_{2}-l_{1}\right) \Rightarrow 2 \times(24.5-17)\)

\(\Rightarrow 2 \times 7.5=15 cm\)

\(\& v = f \lambda \Rightarrow 330=\lambda \times 15 \times 10^{-2}\)

\(\lambda=\frac{330}{15} \times 100 \Rightarrow \frac{1100 \times 100}{5}\)

\(\Rightarrow 2200 Hz\)

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