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JEE Mains · Physics · STD 12 - Electromagnetic waves
  • JEE Mains 2022
  • Medium
  • Numerical

The intensity of the light from a bulb incident on a surface is \(0.22 \,W / m ^{2}\). The amplitude of the magnetic field in this light-wave is_______ \(\times 10^{-9} \,T\). (Given : Permittivity of vacuum \(\epsilon_{0}=8.85 \times 10^{-12} \,C ^{2} N ^{-1} m ^{-2}\), speed of light in vacuum \(c =3 \times 10^{8} \,ms ^{-1}\) )

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Answer & Solution

Correct Answer

(B) \(43\)

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Detailed explanation

\(I =\left(\frac{1}{2} \varepsilon_{0} E _{0}^{2}\right) C\)

\(\Rightarrow E _{0} \Rightarrow \sqrt{\frac{2 I }{\varepsilon_{0} C }} \Rightarrow \sqrt{\frac{2 \times 0.22}{8.85 \times 10^{-12} \times 3 \times 10^{8}}}=12.873\)

\(B \Rightarrow \frac{ E _{0}}{ C } \Rightarrow \frac{12.873}{3 \times 10^{8}}=4.291 \times 10^{-8}=43 \times 10^{-9}\)

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