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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2020
  • Easy
  • MCQ

For a transverse wave travelling along a straight line, the distance between two peaks (crests) is \(5 \,m ,\) while the distance between one crest and one trough is \(1.5 \,m\) The possible wavelengths (in \(m\) ) of the waves are

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Answer & Solution

Correct Answer

(D) \(\frac{1}{1}, \frac{1}{3}, \frac{1}{5}, \ldots\)

Step-by-step Solution

Detailed explanation

Given \(T\) to \(C\,\, 1.5 m\)

\(C\) to \(C\, 5 m\)

\(T\) to \(C =\left(2 n _{1}+1\right) \frac{\lambda}{2}\)

\(C\) to \(C = n _{2} \lambda\)

\(\frac{1.5}{5}=\frac{\left(2 n _{1}+1\right)}{2 n _{2}} \Rightarrow 3 n _{2}=10 n _{1}+5\)

\(n _{1}=1, n _{2}=5 \rightarrow \lambda=1\)

\(n _{1}=4, n _{2}=15 \rightarrow \lambda=1 / 3\)

\(n _{1}=7, n _{2}=25 \rightarrow \lambda=1 / 5\)

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