JEE Mains · Physics · STD 11 - 14. waves and sound
For a transverse wave travelling along a straight line, the distance between two peaks (crests) is \(5 \,m ,\) while the distance between one crest and one trough is \(1.5 \,m\) The possible wavelengths (in \(m\) ) of the waves are
- A \(1,2,3, \ldots \ldots\)
- B \(\frac{1}{2}, \frac{1}{4}, \frac{1}{6}, \ldots\)
- C \(1,3,5, \ldots\)
- D \(\frac{1}{1}, \frac{1}{3}, \frac{1}{5}, \ldots\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{1}, \frac{1}{3}, \frac{1}{5}, \ldots\)
Step-by-step Solution
Detailed explanation
Given \(T\) to \(C\,\, 1.5 m\) \(C\) to \(C\, 5 m\) \(T\) to \(C =\left(2 n _{1}+1\right) \frac{\lambda}{2}\) \(C\) to \(C = n _{2} \lambda\) \(\frac{1.5}{5}=\frac{\left(2 n _{1}+1\right)}{2 n _{2}} \Rightarrow 3 n _{2}=10 n _{1}+5\) \(n _{1}=1, n _{2}=5 \rightarrow \lambda=1\)…
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