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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2020
  • Easy
  • MCQ

Speed of a transverse wave on a straight wire (mass \(6.0\; \mathrm{g}\), length \(60\; \mathrm{cm}\) and area of cross-section \(1.0\; \mathrm{mm}^{2}\) ) is \(90\; \mathrm{ms}^{-1} .\) If the Young's modulus of wire is \(16 \times 10^{11}\; \mathrm{Nm}^{-2},\) the extension of wire over its natural length is

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Answer & Solution

Correct Answer

(C) \(0.03\; mm\)

Step-by-step Solution

Detailed explanation

\(\mathrm{v}=\sqrt{\frac{\mathrm{T}}{\mu}}\)

\(90=\sqrt{\frac{\mathrm{YA}}{\mathrm{m}}}=\sqrt{\frac{16 \times 10^{11} \times 10^{-6} \times \Delta l}{6 \times 10^{-3}}}\)

\(=\frac{8100 \times 3}{8} \times 10^{-8}=\Delta l=0.03\;mm\)

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