JEE Mains · Physics · STD 11 - 14. waves and sound
Speed of a transverse wave on a straight wire (mass \(6.0\; \mathrm{g}\), length \(60\; \mathrm{cm}\) and area of cross-section \(1.0\; \mathrm{mm}^{2}\) ) is \(90\; \mathrm{ms}^{-1} .\) If the Young's modulus of wire is \(16 \times 10^{11}\; \mathrm{Nm}^{-2},\) the extension of wire over its natural length is
- A \(0.02\; mm\)
- B \(0.04\; mm\)
- C \(0.03\; mm\)
- D \(0.01\; mm\)
Answer & Solution
Correct Answer
(C) \(0.03\; mm\)
Step-by-step Solution
Detailed explanation
\(\mathrm{v}=\sqrt{\frac{\mathrm{T}}{\mu}}\) \(90=\sqrt{\frac{\mathrm{YA}}{\mathrm{m}}}=\sqrt{\frac{16 \times 10^{11} \times 10^{-6} \times \Delta l}{6 \times 10^{-3}}}\) \(=\frac{8100 \times 3}{8} \times 10^{-8}=\Delta l=0.03\;mm\)
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