JEE Mains · Physics · STD 12 - 12. atoms
As per given figure \(A , B\) and \(C\) are the first, second and third excited energy level of hydrogen atom respectively. If the ratio of the two wavelengths \(\left(\right.\) i.e. \(\left.\frac{\lambda_1}{\lambda_2}\right)\) is \(\frac{7}{4 n}\), then the value of \(n\) will be
- A \(5\)
- B \(10\)
- C \(15\)
- D \(20\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
As \(\frac{1}{\lambda}=R Z^2\left[\frac{1}{ n _1^2}-\frac{1}{ n _2^2}\right]\) \(\frac{1}{\lambda_1}=R(1)^2\left[\frac{1}{(2)^2}-\frac{1}{(3)^2}\right]=R\left(\frac{5}{36}\right)\)…
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