JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Given below are two statements: one is labelled a Assertion \((A)\) and the other is labelled as Reason\((R)\) \(Assertion\) \((A)\) : Work done by electric field on moving a positive charge on an equipotential surface is always zero. \(Reason\) \((R)\) : Electric lines of forces are always perpendicular to equipotential surfaces. In the light of the above statements, choose the most appropriate answer from the options given below
- A Both \((A)\) and \((R)\) are correct but \((R)\) is not the correct explanation of \((\mathrm{A})\)
- B \((A)\) is correct but \((R)\) is not correct
- C \((A)\) is not correct but \((R)\) is correct
- D Both \((A)\) and \((R)\) are correct and \((R)\) is the correct explanation of \((A)\)
Answer & Solution
Correct Answer
(D) Both \((A)\) and \((R)\) are correct and \((R)\) is the correct explanation of \((A)\)
Step-by-step Solution
Detailed explanation
Electric line of force are always perpendicular to equipotential surface so angle between farce and displacement will always be \(90^{\circ}\). So work done equal to \(0\) .
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