JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2024
- Hard
- MCQ
Given below are two statements: one is labelled a Assertion \((A)\) and the other is labelled as Reason\((R)\) \(Assertion\) \((A)\) : Work done by electric field on moving a positive charge on an equipotential surface is always zero. \(Reason\) \((R)\) : Electric lines of forces are always perpendicular to equipotential surfaces. In the light of the above statements, choose the most appropriate answer from the options given below
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) Both \((A)\) and \((R)\) are correct and \((R)\) is the correct explanation of \((A)\)
Step-by-step Solution
Detailed explanation
Electric line of force are always perpendicular to equipotential surface so angle between farce and displacement will always be \(90^{\circ}\). So work done equal to \(0\) .
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