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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance

Given below are two statements: one is labelled a Assertion \((A)\) and the other is labelled as Reason\((R)\) \(Assertion\) \((A)\) : Work done by electric field on moving a positive charge on an equipotential surface is always zero. \(Reason\) \((R)\) : Electric lines of forces are always perpendicular to equipotential surfaces. In the light of the above statements, choose the most appropriate answer from the options given below 

  1. A  Both \((A)\) and \((R)\) are correct but \((R)\) is not the correct explanation of \((\mathrm{A})\)
  2. B \((A)\) is correct but \((R)\) is not correct
  3. C  \((A)\) is not correct but \((R)\) is correct
  4. D  Both \((A)\) and \((R)\) are correct and \((R)\) is the correct explanation of \((A)\)
Verified Solution

Answer & Solution

Correct Answer

(D)  Both \((A)\) and \((R)\) are correct and \((R)\) is the correct explanation of \((A)\)

Step-by-step Solution

Detailed explanation

Electric line of force are always perpendicular to equipotential surface so angle between farce and displacement will always be \(90^{\circ}\). So work done equal to \(0\) .
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