JEE Mains · Physics · STD 12 -7. Alternating current
In the given circuit the \({AC}\) source has \(\omega=100\, {rad} {s}^{-1}\). Considering the inductor and capacitor to be ideal, what will be the current \(I\) flowing through the circuit? (in \(A\))

- A \(5.9\)
- B \(3.16\)
- C \(0.94\)
- D \(6\)
Answer & Solution
Correct Answer
(B) \(3.16\)
Step-by-step Solution
Detailed explanation
\(Z_{{c}}=\sqrt{\left(\frac{1}{\omega {C}}\right)^{2}+{R}^{2}}\) \(=\sqrt{\left(\frac{1}{100 \times 100 \times 10^{-6}}\right)^{2}+100^{2}}\) \({Z}_{{C}}=\sqrt{(100)^{2}+(100)^{2}}\) \(=100 \sqrt{2}\) \({Z}_{{L}}=\sqrt{(\omega {L})^{2}+{R}^{2}}\)…
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