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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2022
  • Medium
  • MCQ

The magnetic field at the centre of a circular coil of radius \(I\), due to current I flowing through it, is \(B\). The magnetic field at a point along the axis at a distance \(\frac{r}{2}\) from the centre is

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Answer & Solution

Correct Answer

(C) \(\left(\frac{2}{\sqrt{5}}\right)^{3} B\)

Step-by-step Solution

Detailed explanation

\(B_{C}=\frac{\mu_{0} I}{2 r}, B_{a}=\frac{\mu_{0} I^{2}}{2\left(x^{2}+r^{2}\right)^{3 / 2}}\)

\(At \,\,x =\frac{r}{2}\)

\(B _{ a }=\frac{\mu_{0} Ir ^{2}}{2\left(\frac{ r ^{2}}{4}+ r ^{2}\right)^{3 / 2}}\)

\(=\frac{\mu_{0} Ir ^{2}}{2\left(\frac{5}{4} r ^{2}\right)^{3 / 2}}=\frac{\mu_{0} I }{2 r }\left(\frac{4}{5}\right)^{3 / 2}\)

\(=\frac{\mu_{0} I }{2 r }\left(\frac{2}{\sqrt{5}}\right)^{3}\)

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