JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2025
- Medium
- MCQ
Current passing through a wire as function of time is given as \(\mathrm{I}(\mathrm{t})=0.02 \mathrm{t}+0.01 \mathrm{~A}\). The charge that will flow through the wire from \(t=1 s\) to \(t=2 s\) is :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) 0.04 C
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{q}=\int \mathrm{idt} \\ & \int_0^2(0.02 \mathrm{t}+0.01) \mathrm{dt}\end{aligned}\)
\(\begin{aligned} & \mathrm{q}=\left[0.02 \frac{\mathrm{t}^2}{2}+0.01 \mathrm{t}\right]_1^2 \\ & =0.01(3)+0.01(1) \\ & =0.04 \mathrm{C}\end{aligned}\)
\(\begin{aligned} & \mathrm{q}=\left[0.02 \frac{\mathrm{t}^2}{2}+0.01 \mathrm{t}\right]_1^2 \\ & =0.01(3)+0.01(1) \\ & =0.04 \mathrm{C}\end{aligned}\)
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