JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division \(=0.05 mm\), then the least count of the vernier callipers is _________ mm.
- A 0.002
- B 0.05
- C 0.02
- D 0.005
Answer & Solution
Correct Answer
(A) 0.002
Step-by-step Solution
Detailed explanation
\(LC =1 MSD -1 MSD =1 MSD -\frac{48}{50} MSD\) \(=\frac{2}{50} MSD =\frac{2}{50} \times .05 mm=0.002 mm\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- The correct truth table for the following logic circuit is _______.
JEE Mains 2024 Hard - A light string passing over a smooth light pulley connects two blocks of masses \(m_1\) and \(m_2\) (where \(m_2>m_1\) ). If the acceleration of the system is \(\frac{\mathrm{g}}{\sqrt{2}}\), then the ratio of the masses \(\frac{\mathrm{m}_1}{\mathrm{~m}_2}\) is _______.JEE Mains 2024 Hard
- The disintegration energy \(Q\) for the nuclear fission of \({ }^{235} \mathrm{U} \rightarrow{ }^{140} \mathrm{Ce}+{ }^{94} \mathrm{Zr}+\mathrm{n}\) is _______ \(\mathrm{MeV}\). Given atomic masses of \({ }^{235} \mathrm{U}: 235.0439 \mathrm{u},{ }^{140} \mathrm{Ce} ; 139.9054 \mathrm{u},\) \({ }^{94} \mathrm{Zr}: 93.9063 \mathrm{u} ; \mathrm{n}: 1.0086 \mathrm{u},\) Given Value of \(\mathrm{c}^2=931 \mathrm{MeV} / \mathrm{u}\)JEE Mains 2024 Hard
- If the percentage errors in measuring the length and the diameter of a wire are \(0.1 \%\) each. The percentage error in measuring its resistance will be _______.JEE Mains 2024 Hard
- An experiment takes \(10\, minutes\) to raise the temperature of water in a container from \(0\,^oC\) to \(100\,^oC\) and another \(55\, minutes\) to convert it totally into steam by a heater supplying heat at a uniform rate . Neglecting the specific heat of the container and taking specific heat of water to be \(1\, cal / g\,^oC\), the heat of vapourization according to this experiment will come out to be ........ \(cal/g\)JEE Mains 2015 Medium
- The current flowing through a conductor connected across a source is \(2\,A\) and \(1.2\,A\) at \(0^{\circ}\,C\) and \(100^{\circ}\,C\) respectively. The current flowing through the conductor at \(50^{\circ}\,C\) will be \(......\times 10^2\,mA\).JEE Mains 2023 Hard
More PYQs from JEE Mains
- Let \(f :(0, \infty) \rightarrow(0, \infty)\) be a differentiable function such that \(f(1)= e\) and \(\lim \limits_{t \rightarrow x} \frac{t^{2} f^{2}(x)-x^{2} f^{2}(t)}{t-x}=0\) If \(f ( x )=1,\) then \(x\) is equal toJEE Mains 2020 Hard
- If \(X = \{ {4^n} - 3n - 1:n \in N\} \) and \(Y = \{ 9(n - 1):n \in N\} ,\) then \(X \cup Y\) = . . . . .JEE Mains 2014 Medium
- If the r.m.s. speed of chlorine molecule is \(490\,m / s\) at \(27^{\circ}\,C\), the r.m.s. speed of argon molecules at the same temperature will be \(......\,m/s\) (Atomic mass of argon \(=39.9\,u\), molecular mass of chlorine \(=70.9\,u )\)JEE Mains 2023 Easy
- Three defective oranges are accidently mixed with seven good ones and on looking at them, it is not possible to differentiate between them. Two oranges are drawn at random from the lot. If \(x\) denote the number of defective oranges, then the variance of \(x\) isJEE Mains 2025 Medium
- Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Time period of a simple pendulum is longer at the top of a mountain than that at the base of the mountain.
Reason (R): Time period of a simple pendulum decreases with increasing value of acceleration due to gravity and vice-versa.
In the light of the above statements, choose the most appropriate answer from the options given below :JEE Mains 2025 Easy - An object is placed in a medium of refractive index \(3\). An electromagnetic wave of intensity \(6 \times 10^8 \mathrm{~W} / \mathrm{m}^2\) falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space \(=3 \times 10^8 \mathrm{~m} / \mathrm{s}\) ):JEE Mains 2024 Hard