JEE Mains · Maths · STD 12 - 11. three dimension geometry
If the plane \(P\) passes through the intersection of two mutually perpendicular planes \(2 x + ky -5 z =\) 1 and \(3 kx - ky + z =5, k <3\) and intercepts a unit length on positive \(x\)-axis, then the intercept made by the plane \(P\) on the \(y\)-axis is
- A \(\frac{1}{11}\)
- B \(\frac{5}{11}\)
- C \(6\)
- D \(7\)
Answer & Solution
Correct Answer
(D) \(7\)
Step-by-step Solution
Detailed explanation
Two given planes mutually perpendicular \(2(3 k )+ k (- k )+(-5) 1=0\) \(k =1,5\) but \(k <3\) So \(k =1\) Plane passing through these planes is \(2 x+y-5 z-1+\lambda(3 x-y+z-5)=0\)…
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