\(L\), \(C\) and \(R\) represents physical quantities inductance, capacitance and resistance respectively. The dimensional formula \(ML^2 T^{-4} A^{-2}\) corresponds to __________.

Dimensional formula of inductance \(L\) is obtained from \(E = \dfrac{1}{2}LI^2\):

\([L] = \dfrac{[E]}{[I]^2} = \dfrac{ML^2T^{-2}}{A^2} = ML^2T^{-2}A^{-2}\)

Dimensional formula of capacitance \(C\) is obtained from \(E = \dfrac{1}{2}\dfrac{Q^2}{C}\):

\([C] = \dfrac{[Q]^2}{[E]} = \dfrac{A^2T^2}{ML^2T^{-2}} = M^{-1}L^{-2}T^4A^2\)

Dimensional formula of resistance \(R\) is obtained from \(P = I^2R\):

\([R] = \dfrac{[P]}{[I]^2} = \dfrac{ML^2T^{-3}}{A^2} = ML^2T^{-3}A^{-2}\)

The dimensional formula of \(\sqrt{LC}\) is:

\([\sqrt{LC}] = \sqrt{(ML^2T^{-2}A^{-2})(M^{-1}L^{-2}T^4A^2)} = \sqrt{T^2} = T\)

Evaluating the dimensional formula of \(\dfrac{R}{\sqrt{LC}}\):

\(\left[\dfrac{R}{\sqrt{LC}}\right] = \dfrac{ML^2T^{-3}A^{-2}}{T} = ML^2T^{-4}A^{-2}\)

This matches the given dimensional formula.

Answer: \(\dfrac{R}{\sqrt{LC}}\)