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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2023
  • Medium
  • MCQ

A point charge of \(10\,\mu C\) is placed at the origin. At what location on the \(X\)-axis should a point charge of \(40\,\mu\,C\) be placed so that the net electric field is zero at \(x =2\,cm\) on the \(X\)-axis ?

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Answer & Solution

Correct Answer

(A) \(x =6\,cm\)

Step-by-step Solution

Detailed explanation

\(E _{ P }=\frac{ K \times 10}{2^2}-\frac{ K \times 40}{\left( x _0-2\right)^2}=0\)

\(\frac{1}{2}=\frac{2}{x_0-2}\)

\(x_0-2=4\)

\(x_0=6\,cm\)

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