JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The helium and argon are put in the flask at the same room temperature ( 300 K). The ratio of average kinetic energies (per molecule) of helium and argon is :
(Give : Molar mass of helium \(=4 \mathrm{~g} / \mathrm{mol}\), Molar mass of argon \(=40 \mathrm{~g} / \mathrm{mol}\))
- A \(1: 10\)
- B \(10: 1\)
- C \(1: \sqrt{10}\)
- D \(1: 1\)
Answer & Solution
Correct Answer
(D) \(1: 1\)
Step-by-step Solution
Detailed explanation
\(K. E=\frac{f}{2} K T\) For He and \(\mathrm{Ar}=3\) \(\frac{\mathrm{K} \cdot \mathrm{E}_{\mathrm{He}}}{\mathrm{~K} \cdot \mathrm{E}_{\mathrm{Ar}}}=\frac{1}{1}\)
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