JEE Mains · Physics · STD 11- 8. mechanical properties of solids
A wire of length \(L\) and radius \(r\) is clamped rigidly at one end. When the other end of the wire is pulled by a force \(f\), its length increases by \(l\). Another wire of same material of length \(2 L\) and radius \(2 r\) is pulled by a force \(2 f\). Then the increase in its length will be
- A \(2\,l\)
- B \(l\)
- C \(4 \ l\)
- D \(l / 2\)
Answer & Solution
Correct Answer
(B) \(l\)
Step-by-step Solution
Detailed explanation
\(\frac{2 f }{\pi(2 r )^2}= Y \frac{\ell^{\prime}}{2 L }\) \(\Rightarrow \frac{2}{1}=\frac{2 \ell^{\prime}}{\ell} \Rightarrow \ell^{\prime}=\ell\)
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