JEE Mains · Physics · STD 12 - 12. atoms
For hydrogen atom, \(\lambda_1\) and \(\lambda_2\) are the wavelengths corresponding to the transitions \(1\) and \(2\) respectively as shown in figure. The ratio of \(\lambda_1\) and \(\lambda_2\) is \(\frac{x}{32}\). The value of \(x\) is \(..........\)
- A \(27\)
- B \(26\)
- C \(25\)
- D \(24\)
Answer & Solution
Correct Answer
(A) \(27\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{\lambda}= Rz ^2\left[\frac{1}{ n _1^2}-\frac{1}{ n _2^2}\right]\) \(\frac{1}{\lambda_1}= Rz ^2\left[\frac{1}{1^2}-\frac{1}{3^2}\right]=\frac{8}{9} Rz ^2\) \(\frac{1}{\lambda_2}= Rz ^2\left[\frac{1}{1^2}-\frac{1}{2^2}\right]=\frac{3}{4} Rz ^2\)…
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