JEE Mains · Physics · STD 12 - 3. current electricity
At room temperature \(\left(27^{\circ} \mathrm{C}\right)\), the resistance of a heating element is \(50 \Omega\). The temperature coefficient of the material is \(2.4 \times 10^{-4}{ }^{\circ} \mathrm{C}^1\). The temperature of the element, when its resistance is \(62 \Omega\) is _______ \({ }^{\circ} \mathrm{C}\).
- A \(1026\)
- B \(1027\)
- C \(1028\)
- D \(1029\)
Answer & Solution
Correct Answer
(B) \(1027\)
Step-by-step Solution
Detailed explanation
\(\mathrm{R}=\mathrm{R}_0(1+\alpha \Delta \mathrm{T})\) \(62=50\left\lfloor 1+2.4 \times 10^{-4} \Delta \mathrm{T}\right\rfloor\) \(\Delta \mathrm{T}=1000^{\circ} \mathrm{C}\) \(\Rightarrow \mathrm{T}-27^{\circ}=1000^{\circ} \mathrm{C}\) \(\mathrm{T}=1027^{\circ} \mathrm{C}\)
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