JEE Mains · Physics · STD 12 - 10. Wave optics
Two plane polarized light waves combine at a certain point whose electric field components are :
\(\begin{aligned} & \mathrm{E}_1=\mathrm{E}_0 \sin \omega \mathrm{t} \\ & \mathrm{E}_2=\mathrm{E}_0 \sin \left(\omega \mathrm{t}+\frac{\pi}{3}\right)\end{aligned}\)
Find the amplitude of the resultant wave.
- A 0.9 E
- B \(\mathrm{E}_0\)
- C \(1.7 \mathrm{E}_0\)
- D \(3.4 \mathrm{E}_0\)
Answer & Solution
Correct Answer
(C) \(1.7 \mathrm{E}_0\)
Step-by-step Solution
Detailed explanation
\(\mathrm{E}=\sqrt{\left(\mathrm{E}_0\right)^2+\left(\mathrm{E}_0\right)^2+2\left(\mathrm{E}_0\right)\left(\mathrm{E}_0\right) \cos \frac{\pi}{3}}\) \(\mathrm{E}=\sqrt{2 \mathrm{E}_0^2+\mathrm{E}_0^2}=\sqrt{3} \mathrm{E}_0=1.73 \mathrm{E}_0\)
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