JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young's double slit experiment two slits are separated by \(2\, mm\) and the screen is placed one meter away. When a light of wavelength \(500 \,nm\) is used, the fringe separation will be ........ \(mm\)
- A \(0.25\)
- B \(0.50\)
- C \(0.75\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(0.25\)
Step-by-step Solution
Detailed explanation
\(\beta=\frac{\lambda D }{ d }=\frac{500 \times 10^{-9} \times 1}{2 \times 10^{-3}}\) \(\beta=\frac{5}{2} \times 10^{-4} m =2.5 \times 10^{-1} mm\) \(b =0.25 mm\)
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