JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2026
- Medium
- Numerical
10 mole of oxygen is heated at constant volume from \(30^{\circ} C\) to \(40^{\circ} C\). The change in the internal energy of the gas is _________ cal. (The molecular specific heat of oxygen at constant pressure, \(C _{ p }=7 cal . / mol ^{\circ} C\) and \(\left.R =2 cal . / mol ^{\circ} C .\right)\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) 500
Step-by-step Solution
Detailed explanation
\(\Delta U = nC _{ v } \Delta T\)
\(=n\left(C_P-R\right) \Delta T\)
\(=10(7-2)(40-30)\)
\(\Delta U =500\)
\(=n\left(C_P-R\right) \Delta T\)
\(=10(7-2)(40-30)\)
\(\Delta U =500\)
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