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JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
  • JEE Mains 2016
  • Hard
  • MCQ

A simple pendulum made of a bob of mass \(m\) and a metallic wire of negligible mass has time period \(2s\) at  \(T = 0\,^oC\) . If the temeprature of the wire is increased and the corresponding change in its time peirod is plotted against its temperature, the resulting graph is a line of slope \(S\). If the coefficient of linear expansion of metal is \(\alpha \) then the value of  \(S\) is

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Answer & Solution

Correct Answer

(C) \(\alpha \)

Step-by-step Solution

Detailed explanation

If coefficient of liner expansion is \(\alpha \) then

\(\Delta T = \frac{1}{2}T\,\alpha \,d\,\theta \)

\( \Rightarrow \frac{{\Delta T}}{{d\theta }} = \frac{T}{2}\alpha \)

\(But\,T = 2s\)

\(\therefore \,Line\,of\,slope\,S = \frac{{\Delta T}}{{d\theta }} = \alpha .\)

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