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JEE Mains · Physics · STD 11 - 9.2 surface tension
On heating water, bubbles being formed at the bottom of the vessel detach and rise. Take the bubbles to be spheres of radius \(R\) and making a circular contact of radius \(r\) with the bottom of the vessel. If \(r < < R\), and the surface tension of water is \(T\), value of \(r\) just before bubbles detach is (density of water is \(\rho_{w}\))

- A \(R^{2} \sqrt{\frac{\rho_{w} g}{T}}\)
- B \(R^{2} \sqrt{\frac{2 \rho_{w} g}{3 T}}\)
- C \(R^{2} \sqrt{\frac{3 \rho_{w} g}{T}}\)
- D \(R^{2} \sqrt{\frac{\rho_{w} g}{6 T}}\)
Answer & Solution
Correct Answer
(B) \(R^{2} \sqrt{\frac{2 \rho_{w} g}{3 T}}\)
Step-by-step Solution
Detailed explanation
When the bubble gets detached, Buoyant force = force due to surface tension \(\int T \times d l \sin \theta=\frac{4}{3} \pi R^{3} \rho_{w} g\) \(\Rightarrow T \times 2 \pi r \times \frac{r}{R}=\frac{4}{3} \pi R^{3} \rho_{w} g\)…
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