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JEE Mains · Physics · STD 11 - Surface tension
  • JEE Mains 2014
  • Hard
  • MCQ

On heating water, bubbles being formed at the bottom of the vessel detach and rise. Take the bubbles to be spheres of radius \(R\) and making a circular contact of radius \(r\) with the bottom of the vessel. If \(r < < R\), and the surface tension of water is \(T\), value of \(r\) just before bubbles detach is (density of water is \(\rho_{w}\))

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Answer & Solution

Correct Answer

(B) \(R^{2} \sqrt{\frac{2 \rho_{w} g}{3 T}}\)

Step-by-step Solution

Detailed explanation

When the bubble gets detached,

Buoyant force = force due to surface tension

\(\int T \times d l \sin \theta=\frac{4}{3} \pi R^{3} \rho_{w} g\)

\(\Rightarrow T \times 2 \pi r \times \frac{r}{R}=\frac{4}{3} \pi R^{3} \rho_{w} g\)

\(\Rightarrow r^{2}=\frac{2 R^{4} \rho_{w g} g}{3}\)

\(\Rightarrow r=R^{2} \sqrt{\frac{2 \rho_{w D g}}{3 T}}\)

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