JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
Three long straight wires carrying current are arranged mutually parallel as shown in the figure. The force experienced by 15 cm length of wire Q is ___________.
\(\left(\mu_0=4 \pi \times 10^{-7} T . m / A \right)\)
- A \(6 \times 10^{-7}\) N towards P
- B \(6 \times 10^{-6}\) N towards R
- C \(6 \times 10^{-7}\) N towards R
- D \(6 \times 10^{-6}\) N towards P
Answer & Solution
Correct Answer
(B) \(6 \times 10^{-6}\) N towards R
Step-by-step Solution
Detailed explanation
\(F _{ net }=\frac{\mu_0}{2 \pi} I _0\left(\frac{ I _1}{d_1}+\frac{ I _2}{d_2}\right) \ell\) \(F _{ net }=2 \times 10^{-7} \times 1\left(\frac{3}{3}+\frac{2}{2}\right) \times \frac{15 \times 10^{-2}}{10^{-2}}\) \(=4 \times 15 \times 10^{-7}\)…
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