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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2021
  • Medium
  • Numerical

In an electric circuit, a cell of certain emf provides a potential difference of \(1.25\, {V}\) across a load resistance of \(5\, \Omega .\) However, it provides a potential difference of \(1\, {V}\) across a load resistance of \(2\, \Omega\). The \(emf\) of the cell is given by \(\frac{x}{10} v\). Then the value of \(x\) is ..... .

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Answer & Solution

Correct Answer

(B) \(15\)

Step-by-step Solution

Detailed explanation

Terminal voltage \(v=i R=\frac{E R}{R+r}\)

\(1^{s t} \rightarrow 1.25=\frac{E(5)}{5+r} . .(i)\)

\(2^{n d} \rightarrow 1=\frac{E(2)}{2+r}\, \cdots \text { (ii) }\)

By \((i)\) and \((ii)\)

\(r=1 \,\Omega, E=\frac{3}{2} \,V=\frac{15}{10}\, \text { volt }\)

\(\Rightarrow {x}=15\)

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