JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2021
- Medium
- Numerical
In an electric circuit, a cell of certain emf provides a potential difference of \(1.25\, {V}\) across a load resistance of \(5\, \Omega .\) However, it provides a potential difference of \(1\, {V}\) across a load resistance of \(2\, \Omega\). The \(emf\) of the cell is given by \(\frac{x}{10} v\). Then the value of \(x\) is ..... .
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(15\)
Step-by-step Solution
Detailed explanation
Terminal voltage \(v=i R=\frac{E R}{R+r}\)
\(1^{s t} \rightarrow 1.25=\frac{E(5)}{5+r} . .(i)\)
\(2^{n d} \rightarrow 1=\frac{E(2)}{2+r}\, \cdots \text { (ii) }\)
By \((i)\) and \((ii)\)
\(r=1 \,\Omega, E=\frac{3}{2} \,V=\frac{15}{10}\, \text { volt }\)
\(\Rightarrow {x}=15\)
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