JEE Mains · Physics · STD 12 -7. Alternating current
\(AC\) alternating emf \(\mathrm{E}=110 \sqrt{2} \sin 100 \mathrm{t}\) volt is applied to a capacitor of \(2 \mu \mathrm{F}\), the rms value of current in the circuit is _______ \(\mathrm{mA}\).
- A \(22\)
- B \(20\)
- C \(25\)
- D \(30\)
Answer & Solution
Correct Answer
(A) \(22\)
Step-by-step Solution
Detailed explanation
\(C=2 \mu f ; \quad E=110 \sqrt{2} \sin (100 \mathrm{t})\) \(\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega c}=\frac{1}{100 \times 2 \times 10^6}\) \(=\frac{10000}{2}=5000 \Omega\) \(\mathrm{i}_0=\frac{110 \sqrt{2}}{5000}\)…
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