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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2024
  • Hard
  • Numerical

\(AC\) alternating emf \(\mathrm{E}=110 \sqrt{2} \sin 100 \mathrm{t}\) volt is applied to a capacitor of \(2 \mu \mathrm{F}\), the rms value of current in the circuit is _______ \(\mathrm{mA}\).

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Answer & Solution

Correct Answer

(A) \(22\)

Step-by-step Solution

Detailed explanation

\(C=2 \mu f ; \quad E=110 \sqrt{2} \sin (100 \mathrm{t})\)

\(\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega c}=\frac{1}{100 \times 2 \times 10^6}\)

\(=\frac{10000}{2}=5000 \Omega\)

\(\mathrm{i}_0=\frac{110 \sqrt{2}}{5000}\)

\(\mathrm{i}_{\mathrm{rms}}=\frac{110 \sqrt{2}}{5000 \sqrt{2}}\)

\(=\frac{110}{5} \mathrm{~mA}\)

\(=22 \mathrm{~mA}\)

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