JEE Mains · Physics · STD 11 - 11. thermodynamics
A real gas within a closed chamber at \(27^{\circ} \mathrm{C}\) undergoes the cyclic process as shown in figure. The gas obeys \(P V^3=\mathrm{RT}\) equation for the path \(A\) to \(B\). The net work done in the complete cycle is _______.(assuming \(R=8 \mathrm{~J} / \mathrm{molK}\) )
- A \(225 \mathrm{~J}\)
- B \(205 \mathrm{~J}\)
- C \(20 \mathrm{~J}\)
- D \(-20 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(205 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{W}_{\mathrm{AB}} =\int \mathrm{PdV} \quad \text { (Assuming } \mathrm{T} \text { to be constant) }\) \(=\int \frac{\mathrm{RTdV}}{\mathrm{V}^3}\) \(=\mathrm{RT} \int_2^4 \mathrm{~V}^{-3} \mathrm{dV}\)…
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