JEE Mains · Physics · STD 12 - 3. current electricity
In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line. One may conclude that:

- A \(R\left( T \right) = {R_o}{e^{{T^2}/T_0^2}}\)
- B \(R\left( T \right) = \frac{{{R_o}}}{{{T^2}}}\)
- C \(R\left( T \right) = {R_o}{e^{-{T^2}/T_0^2}}\)
- D \(R\left( T \right) = {R_o}{e^{T_0^2/{T^2}}}\)
Answer & Solution
Correct Answer
(C) \(R\left( T \right) = {R_o}{e^{-{T^2}/T_0^2}}\)
Step-by-step Solution
Detailed explanation
\(\frac{\frac{1}{T^{2}}}{\frac{1}{T_{0}^{2}}}+\frac{\ln R(T)}{\ln R\left(T_{0}\right)}=1\) \(\Rightarrow \ln \mathrm{R}(\mathrm{T})=\ln \mathrm{R}\left(\mathrm{T}_{\mathrm{o}}\right)\left(1-\frac{\mathrm{T}_{\mathrm{o}}^{2}}{\mathrm{T}^{2}}\right)\)…
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