JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
An unknown transistor needs to be identified as a \(npn\) or \(pnp\) type. A multimeter, with \(+ve\) and \(-ve\) terminals, is used to measure resistance between different terminals of transistor. If terminal \(2\) is the base of the transistor then which of the following is correct for a \(pnp\) transistor?
- A \(+ve\) terminal \(2,\) \(-ve\) terminal \(3,\) resistance low
- B \(+ve\) terminal \(2,\) \(-ve\) terminal \(1,\) resistane high
- C \(+ve\) terminal \(1 ,\) \(-ve\) terminal \(2,\) resistance high
- D \(+ve\) terminal \(3,\) \(-ve\) terminal \(2,\) resistance high
Answer & Solution
Correct Answer
(C) \(+ve\) terminal \(1 ,\) \(-ve\) terminal \(2,\) resistance high
Step-by-step Solution
Detailed explanation
Connecting circuit according to question, it is clear \(+\,ve\) terminal \(1\), \(-\,ve\) terminal \(2\), resistance high.
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