JEE Mains · Physics · STD 12 - 13. Nuclei
Assuming the experimental mass of \({}^{12}_{6}C\) as \(12\text{ u}\), the mass defect of \({}^{12}_{6}C\) atom is _______ \(\text{MeV}/c^2\).
(Mass of proton \(= 1.00727\text{ u}\), mass of neutron \(= 1.00866\text{ u}\), \(1\text{ u} = 931.5\text{ MeV}/c^2\) and \(c\) is the speed of the light in vacuum).
- A \(127.5\)
- B \(89.03\)
- C \(272.0\)
- D \(92.0\)
Answer & Solution
Correct Answer
(B) \(89.03\)
Step-by-step Solution
Detailed explanation
The mass of \(6\) protons is \(6 \times 1.00727\text{ u} = 6.04362\text{ u}\). The mass of \(6\) neutrons is \(6 \times 1.00866\text{ u} = 6.05196\text{ u}\). Total mass of the constituent nucleons is \(6.04362\text{ u} + 6.05196\text{ u} = 12.09558\text{ u}\). The mass defect…
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