JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
A diverging lens with magnitude of focal length \(25\ cm\) is placed at a distance of \(15\ cm\) from a converging lens of magnitude of focal length \(20\ cm\). A beam of parallel light falls on the diverging lens. The final image formed is
- A real and at a distance of \(40\ cm\) from the divergent lens
- B real and at a distance of \(40\ cm\) from convergent lens
- C virtual and at a distance of \(40\ cm\) from convergent lens.
- D real and at a distance of \(6\ cm\) from the convergent lens
Answer & Solution
Correct Answer
(B) real and at a distance of \(40\ cm\) from convergent lens
Step-by-step Solution
Detailed explanation
As parallel beam incident on diverging lens will form image at focus. \(\therefore \quad v=-25\, \mathrm{cm}\) The image formed by diverging lens is used as an object for converging lens, So for converging lens \(u=-25-15=-40 \,\mathrm{cm}, \quad f=20\, \mathrm{cm}\)…
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