JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2017
- Medium
- MCQ
A diverging lens with magnitude of focal length \(25\ cm\) is placed at a distance of \(15\ cm\) from a converging lens of magnitude of focal length \(20\ cm\). A beam of parallel light falls on the diverging lens. The final image formed is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) real and at a distance of \(40\ cm\) from convergent lens
Step-by-step Solution
Detailed explanation
As parallel beam incident on diverging lens will form image at focus.
\(\therefore \quad v=-25\, \mathrm{cm}\)
The image formed by diverging lens is used as an object for converging lens,
So for converging lens \(u=-25-15=-40 \,\mathrm{cm}, \quad f=20\, \mathrm{cm}\)
\(\therefore \quad\) Final image formed by converging lens
\(\frac{1}{V}-\frac{1}{-40}=\frac{1}{20}\)
or, \(\quad V=40\, \mathrm{cm}\) from converging lens real and inverted.
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