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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2017
  • Medium
  • MCQ

A diverging lens with magnitude of focal length \(25\ cm\) is placed at a distance of \(15\ cm\) from a converging lens of magnitude of focal length \(20\ cm\). A beam of parallel light falls on the diverging lens. The final image formed is

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Answer & Solution

Correct Answer

(B) real and at a distance of \(40\ cm\) from convergent lens

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Detailed explanation

As parallel beam incident on diverging lens will form image at focus.

\(\therefore \quad v=-25\, \mathrm{cm}\)

The image formed by diverging lens is used as an object for converging lens,

So for converging lens \(u=-25-15=-40 \,\mathrm{cm}, \quad f=20\, \mathrm{cm}\)

\(\therefore \quad\) Final image formed by converging lens

\(\frac{1}{V}-\frac{1}{-40}=\frac{1}{20}\)

or, \(\quad V=40\, \mathrm{cm}\) from converging lens real and inverted.

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