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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2018
  • Hard
  • Numerical

A ray of light is incident at an angle of \(60^o\) on one face of a prism of angle \(30^o\) . The emergent ray of light makes an angle of \(30^o\)  with incident ray. The angle made by the emergent ray with second face of prism will be....\(^o\)

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Answer & Solution

Correct Answer

(C) \(90\)

Step-by-step Solution

Detailed explanation

Augle of prism, \(A=30^o,\,\, i=60^o,\)

angle of deviation, \(\delta=30^o\)

Using formula, \(\delta=i+e-A\)

\(\Rightarrow e=\delta+A-i\)

       \(=30^o+30^o-60^o=0^o\)

Emergent ray will be perpendicular to the face

So it will make angle \(90^o\) with the force through which it emerges.

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