JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
A ray of light is incident at an angle of \(60^o\) on one face of a prism of angle \(30^o\) . The emergent ray of light makes an angle of \(30^o\) with incident ray. The angle made by the emergent ray with second face of prism will be....\(^o\)
- A \(30\)
- B \(0\)
- C \(90\)
- D \(45\)
Answer & Solution
Correct Answer
(C) \(90\)
Step-by-step Solution
Detailed explanation
Augle of prism, \(A=30^o,\,\, i=60^o,\) angle of deviation, \(\delta=30^o\) Using formula, \(\delta=i+e-A\) \(\Rightarrow e=\delta+A-i\) \(=30^o+30^o-60^o=0^o\) Emergent ray will be perpendicular to the face So it will make angle \(90^o\) with the force through which it emerges.
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