JEE Mains · Physics · STD 11 - 11. thermodynamics
Given below are two statement Statement \(-I\) : What \(\mu\) amount of an ideal gas undergoes adiabatic change from state \(\left( P _{1}, V _{1}, T _{1}\right)\) to state \(\left( P _{2}, V _{2}, T _{2}\right)\), the work done is \(W =\frac{1 R \left( T _{2}- T _{1}\right)}{1-\gamma}\), where \(\gamma=\frac{ C _{ P }}{ C _{ V }}\) and \(R =\) universal gas constant, Statement \(-II\) : In the above case. when work is done on the gas. the temperature of the gas would rise. Choose the correct answer from the options given below
- A Both statement \(-I\) and statement \(-II\) are true.
- B Both statement \(-I\) and statement \(-II\) are false.
- C Statement \(-I\) is true but statement \(-II\) is false.
- D Statement \(-I\) is false but statement \(-II\) is true.
Answer & Solution
Correct Answer
(A) Both statement \(-I\) and statement \(-II\) are true.
Step-by-step Solution
Detailed explanation
\(W _{\text {adiabatic }}=\frac{ NR \left( T _{f}- T _{ i }\right)}{1-\gamma} \rightarrow\) statment \(1\) \(Q=W+\Delta U\) \(0= W +\Delta U\) \(\Delta U =- W\) If work is done on the gas, i.e. work is negative \(\therefore \Delta U\) is positive. \(\therefore\) Temperature will…
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