JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2022
- Hard
- MCQ
Two identical cells each of emf \(1.5 \,V\) are connected in parallel across a parallel combination voltmeter connected in the circuit measures \(1.2 \,V\). The internal resistance of each cell is.................\(\Omega\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(5\)
Step-by-step Solution
Detailed explanation
\(V = E - ir / 2\)
\(1.2=1.5- i \left(\frac{ r }{2}\right)\)
\(i \frac{ r }{2}=0.3\)
\(i =\frac{1.5}{10+\frac{ r }{2}} \Rightarrow 10 i +\frac{ ir }{2}=1.5\)
\(10 i =1.5-0.3\)
\(i =0.12\, A\)
\(\Rightarrow r =\frac{0.6}{0.12}=5 \,\Omega\)
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