JEE Mains · Physics · STD 12 -7. Alternating current
A direct current of \(4\,A\) and an alternating current of peak value \(4\,A\) flow through resistance of \(3\,\Omega\) and \(2\,\Omega\) respectively. The ratio of heat produced in the two resistances in same interval of time will be.
- A \(3: 2\)
- B \(3: 1\)
- C \(3: 4\)
- D \(4: 3\)
Answer & Solution
Correct Answer
(B) \(3: 1\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} H _{1}=i^{2} R _{1} t & H _{2}=i_{1 ms }^{2} R _{2} t \left\{ i _{1 ms }=\frac{ i _{0}}{\sqrt{2}}\right\} \\ H _{1}=16(3) t \quad H _{2}=\frac{ i _{0}^{2}}{2} R _{2} t \\ H _{2}=16 t \\ H _{1}: H _{2}=3: 1\end{array}\)
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