JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
The total charge on the system of capacitance \(C _{1}=1\,\mu F , C _{2}=2\,\mu F , C _{3}=4\,\mu F\) and \(C _{4}=3\,\mu F\) connected in parallel is \(......\mu C\) (Assume a battery of \(20\,V\) is connected to the combination)
- A \(200\)
- B \(20\)
- C \(10\)
- D \(100\)
Answer & Solution
Correct Answer
(A) \(200\)
Step-by-step Solution
Detailed explanation
Total charge \(= q _{1}+ q _{2}+ q _{2}+ q _{4}\) \(=1 \times 20+2 \times 20+4 \times 20+3 \times 20=200\,\mu C\)
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