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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2024
  • Hard
  • MCQ

The gravitational potential at a point above the surface of earth is \(-5.12 \times 10^7 \mathrm{~J} / \mathrm{kg}\) and the acceleration due to gravity at that point is \(6.4 \mathrm{~m} / \mathrm{s}^2\). Assume that the mean radius of earth to be \(6400 \mathrm{~km}\). The height of this point above the earth's surface is _______.

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Verified Solution

Answer & Solution

Correct Answer

(A) \(1600 \mathrm{~km}\)

Step-by-step Solution

Detailed explanation

\( -\frac{G M_E}{R_E+h}=-5.12 \times 10^{-7} \ldots . \text { (i) } \)

\( \frac{G M_E}{\left(R_E+h\right)^2}=6.4 \ldots \text { (ii) }\)

By \((i)\) and \((ii)\)

\(\Rightarrow h=16 \times 10^5 \mathrm{~m}=1600 \mathrm{~km}\)

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