JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2022
- Hard
- MCQ
The force required to stretch a wire of crosssection \(1 cm ^{2}\) to double its length will be ........ \( \times 10^{7}\,N\) (Given Yong's modulus of the wire \(=2 \times 10^{11}\,N / m ^{2}\) )
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
\(F =Y A \frac{\Delta l}{l}\)
\(=2 \times 10^{11} \times 10^{-4}\left(\frac{2 l-l}{l}\right)\)
\(=2 \times 10^{7}\,N\)
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