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JEE Mains · Physics · STD 11- 8. mechanical properties of solids

The force required to stretch a wire of crosssection \(1 cm ^{2}\) to double its length will be ........ \( \times 10^{7}\,N\) (Given Yong's modulus of the wire \(=2 \times 10^{11}\,N / m ^{2}\) )

  1. A \(1\)
  2. B \(1.5\)
  3. C \(2\)
  4. D \(2.5\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2\)

Step-by-step Solution

Detailed explanation

\(F =Y A \frac{\Delta l}{l}\) \(=2 \times 10^{11} \times 10^{-4}\left(\frac{2 l-l}{l}\right)\) \(=2 \times 10^{7}\,N\)
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