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JEE Mains · Physics · STD 11- Mechanical properties of solids
  • JEE Mains 2022
  • Hard
  • MCQ

The force required to stretch a wire of crosssection \(1 cm ^{2}\) to double its length will be ........ \( \times 10^{7}\,N\) (Given Yong's modulus of the wire \(=2 \times 10^{11}\,N / m ^{2}\) )

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Answer & Solution

Correct Answer

(C) \(2\)

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Detailed explanation

\(F =Y A \frac{\Delta l}{l}\)

\(=2 \times 10^{11} \times 10^{-4}\left(\frac{2 l-l}{l}\right)\)

\(=2 \times 10^{7}\,N\)

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