JEE Mains · Physics · STD 11 - 11. thermodynamics
A closed vessel contains \(0.1\) mole of a monoatomic ideal gas at \(200\, K\). If \(0.05\) mole of the same gas at \(400\, K\) is added to it, the final equilibrium temperature (in \(K\) ) of the gas in the vessel will be closed to
- A \(269.5\)
- B \(260.6\)
- C \(250.5\)
- D \(266.67\)
Answer & Solution
Correct Answer
(D) \(266.67\)
Step-by-step Solution
Detailed explanation
As work done on gas and heat supplied to the gas are zero, total internal energy of gases remain same \(u _{1}+ u _{2}= u _{1}^{\prime}+ u _{2}^{\prime}\) \((0.1) C _{ v }(200)+(0.05) C _{ v }(400)=(0.15) C _{ v } T\) \(T =\frac{800}{3} k =266.67 k\)
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