JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2020
- Medium
- MCQ
A Carnot engine operates between two reservoirs of temperatures \(900\; \mathrm{K}\) and \(300 \;\mathrm{K}\) The engine performs \(1200\; \mathrm{J}\) of work per cycle. The heat energy (in \(\mathrm{J}\) ) delivered by the engine to the low temperature reservoir, in a cycle. is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(600\)
Step-by-step Solution
Detailed explanation
for carnot engine
\(\frac{Q_{1}}{Q_{2}}=\frac{T_{1}}{T_{2}}\)
\(\frac{\mathrm{Q}+1200}{\mathrm{Q}}=\frac{900}{300}\)
\(\mathrm{Q}+1200=3 \mathrm{Q}\)
\(Q=600 \mathrm{J}\)
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