JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2023
- Medium
- Numerical
The resistance of a wire is \(5 \Omega\). It's new resistance in ohm if stretched to \(5\) times of it's original length will be :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(125\)
Step-by-step Solution
Detailed explanation
\(R _{\text {initial }}=\frac{\rho \ell}{ A }=5 \Omega\)
\(\because\) Volume of wire is constant in stretching
\(V _{ i }= V _{ f }\)
\(A _{ i } \ell_{ i }= A _{ f } \ell_{ f }\)
\(A \ell= A ^{\prime}(5 \ell)\)
\(A ^{\prime}=\frac{ A }{5}\)
\(R _{ f }=\frac{\rho \ell_{ f }}{ A _{ f }}=\frac{\rho(5 \ell)}{\left(\frac{ A }{5}\right)}\)
\(=25\left(\frac{\rho \ell}{A}\right)\)
\(=25 \times 5=125 \Omega\)
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