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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2016
  • Hard
  • MCQ

Velocity-time graph for a body of mass \(10\, kg\) is shown in figure. Work-done on the body in first two seconds of the motion is  ................ \(\mathrm{J}\)

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Answer & Solution

Correct Answer

(C) \(-4500\)

Step-by-step Solution

Detailed explanation

Acceleration

\(\left( a \right) = \frac{{v - 4}}{t} = \frac{{\left( {0 - 50} \right)}}{{\left( {10 - 0} \right)}} =  - 5\,m/{s^2}\)

\(u = 50\; m/s\)

\(\therefore  v = u + at =50 - 5t\)

Vwlocity in first two second \(t = 2\)

\({v_{\left( {at\,t = 2} \right)}} = 40\,m/s\)

\(From\, work - energy \,theorem,\)

\(\Delta K.E. = W = \frac{1}{2}\left( {{{40}^2} - {{50}^2}} \right) \times 10 =  - 4500\,J\)

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