JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2016
- Hard
- MCQ
Velocity-time graph for a body of mass \(10\, kg\) is shown in figure. Work-done on the body in first two seconds of the motion is ................ \(\mathrm{J}\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(-4500\)
Step-by-step Solution
Detailed explanation
Acceleration
\(\left( a \right) = \frac{{v - 4}}{t} = \frac{{\left( {0 - 50} \right)}}{{\left( {10 - 0} \right)}} = - 5\,m/{s^2}\)
\(u = 50\; m/s\)
\(\therefore v = u + at =50 - 5t\)
Vwlocity in first two second \(t = 2\)
\({v_{\left( {at\,t = 2} \right)}} = 40\,m/s\)
\(From\, work - energy \,theorem,\)
\(\Delta K.E. = W = \frac{1}{2}\left( {{{40}^2} - {{50}^2}} \right) \times 10 = - 4500\,J\)
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