JEE Mains · Physics · STD 12 - 10. Wave optics
The difference in the number of waves when yellow light propagates through air and vacuum columns of the same thickness is one. The thickness of the air column is \(....\,{mm} .\) [Refractive index of air \(=1.0003\), wavelength of yellow light in vacuum \(=6000 \,\mathring {{A}}\) ]
- A \(2\)
- B \(4\)
- C \(6\)
- D \(8\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
We know Thickness \({t}={n} \lambda\) \({So}, {n} \lambda_{{vac}}=({n}+1) \lambda_{{air}}\) \({n} \lambda=({n}+1) \frac{\lambda}{\mu_{{air}}}\) \(n=\frac{1}{\mu_{\text {air }}-1}=\frac{10^{4}}{3}\) \({t}={n} \lambda\) \(=\frac{10^{4}}{3} \times 6000\, \stackrel{\circ}{{A}}\)…
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