JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2021
- Hard
- Numerical
The difference in the number of waves when yellow light propagates through air and vacuum columns of the same thickness is one. The thickness of the air column is \(....\,{mm} .\) [Refractive index of air \(=1.0003\), wavelength of yellow light in vacuum \(=6000 \,\mathring {{A}}\) ]
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
We know
Thickness \({t}={n} \lambda\)
\({So}, {n} \lambda_{{vac}}=({n}+1) \lambda_{{air}}\)
\({n} \lambda=({n}+1) \frac{\lambda}{\mu_{{air}}}\)
\(n=\frac{1}{\mu_{\text {air }}-1}=\frac{10^{4}}{3}\)
\({t}={n} \lambda\)
\(=\frac{10^{4}}{3} \times 6000\, \stackrel{\circ}{{A}}\)
\(=2\, {mm}\)
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