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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2021
  • Hard
  • Numerical

The difference in the number of waves when yellow light propagates through air and vacuum columns of the same thickness is one. The thickness of the air column is \(....\,{mm} .\) [Refractive index of air \(=1.0003\), wavelength of yellow light in vacuum \(=6000 \,\mathring {{A}}\) ]

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Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

We know

Thickness \({t}={n} \lambda\)

\({So}, {n} \lambda_{{vac}}=({n}+1) \lambda_{{air}}\)

\({n} \lambda=({n}+1) \frac{\lambda}{\mu_{{air}}}\)

\(n=\frac{1}{\mu_{\text {air }}-1}=\frac{10^{4}}{3}\)

\({t}={n} \lambda\)

\(=\frac{10^{4}}{3} \times 6000\, \stackrel{\circ}{{A}}\)

\(=2\, {mm}\)

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