JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2024
- Hard
- MCQ
A wire of length \(L\) and radius \(r\) is clamped at one end. If its other end is pulled by a force \(F\), its length increases by \(l\). If the radius of the wire and the applied force both are reduced to half of their original values keeping original length constant, the increase in length will become _______.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(2\) times
Step-by-step Solution
Detailed explanation
\( \mathrm{Y}=\frac{\text { stress }}{\text { strain }} \)
\( \mathrm{Y}=\frac{\frac{\mathrm{F}}{\mathrm{r}^2}}{\frac{\ell}{\mathrm{L}}} \)
\( \mathrm{F}=\mathrm{Y} \pi \mathrm{r}^2 \times \frac{\ell}{\mathrm{L}} \) \(...........(i)\)
\( \mathrm{Y}=\frac{\frac{\pi \mathrm{r}^2 / 4}{\Delta \ell}}{\mathrm{L}} \)
\( \mathrm{F}=\mathrm{Y} \frac{\Delta \ell}{\mathrm{L}} \times 2 \times \frac{\pi \mathrm{r}^2}{4} \)
\( \text { From }(\mathrm{i}) \)
\( \mathrm{Y} \pi \mathrm{r}^2 \frac{\ell}{\mathrm{L}}=\mathrm{Y} \frac{\Delta \ell}{\mathrm{L}} \frac{\pi \mathrm{r}^2}{2} \)
\( \Delta \ell=2 \ell\)
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