JEE Mains · Physics · STD 11 - Surface tension
- JEE Mains 2024
- Hard
- Numerical
A big drop is formed by coalescing \(1000\) small droplets of water. The ratio of surface energy of \(1000\) droplets to that of energy of big drop is \(\frac{10}{x}\). The value of \(x\) is _______.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
\(1000 \frac{4}{3} \pi \mathrm{r}^3=\frac{4}{3} \pi \mathrm{R}^3\)
\(10 \mathrm{r}=\mathrm{R}\)
\(\mathrm{R}=10 \mathrm{r}\)
\(\frac{\text { S.E. of } 1000 \text { drops }}{\text { S.E. of Big drop }}=\frac{1000\left(4 \pi^2\right) T}{4 \pi R^2 T}\)
\(=\frac{1000 \times \mathrm{r}^2}{(10 \mathrm{r})^2}=10=\frac{10}{\mathrm{x}}\)
\(\therefore \quad \mathrm{x}=1\)
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