JEE Mains · Physics · STD 11 - 9.2 surface tension
A big drop is formed by coalescing \(1000\) small droplets of water. The ratio of surface energy of \(1000\) droplets to that of energy of big drop is \(\frac{10}{x}\). The value of \(x\) is _______.
- A \(5\)
- B \(8\)
- C \(1\)
- D \(3\)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
\(1000 \frac{4}{3} \pi \mathrm{r}^3=\frac{4}{3} \pi \mathrm{R}^3\) \(10 \mathrm{r}=\mathrm{R}\) \(\mathrm{R}=10 \mathrm{r}\) \(\frac{\text { S.E. of } 1000 \text { drops }}{\text { S.E. of Big drop }}=\frac{1000\left(4 \pi^2\right) T}{4 \pi R^2 T}\)…
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