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JEE Mains · Physics · STD 11 - Surface tension
  • JEE Mains 2024
  • Hard
  • Numerical

A big drop is formed by coalescing \(1000\) small droplets of water. The ratio of surface energy of \(1000\) droplets to that of energy of big drop is \(\frac{10}{x}\). The value of \(x\) is _______.

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Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

\(1000 \frac{4}{3} \pi \mathrm{r}^3=\frac{4}{3} \pi \mathrm{R}^3\)

\(10 \mathrm{r}=\mathrm{R}\)

\(\mathrm{R}=10 \mathrm{r}\)

\(\frac{\text { S.E. of } 1000 \text { drops }}{\text { S.E. of Big drop }}=\frac{1000\left(4 \pi^2\right) T}{4 \pi R^2 T}\)

\(=\frac{1000 \times \mathrm{r}^2}{(10 \mathrm{r})^2}=10=\frac{10}{\mathrm{x}}\)

\(\therefore \quad \mathrm{x}=1\)

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